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(32x^2)-3x-6=0
a = 32; b = -3; c = -6;
Δ = b2-4ac
Δ = -32-4·32·(-6)
Δ = 777
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{777}}{2*32}=\frac{3-\sqrt{777}}{64} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{777}}{2*32}=\frac{3+\sqrt{777}}{64} $
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